Մաթեմատիկա 09.09 September 30, 2019October 4, 2019Anahit AvetisyanLeave a comment ax+bx+cx=x(a+b+c)−ax+bx+cx=x(−a+b+c)a³−2a²−a=a(a²−2a−1)m⁴+3m³−m²= m²(m²+3m−1)−2a−ax+ay=a(−2−x+y)5x²−10xy+5y²=5(x²−2xy+y²)5x−15xy+10ax=5x(1−3y+2a)3ab+9ac−12ad=3a(b+3c−4d) 4a²b+a²b²−ab=ab(4a+ab−1)6a³x−a²x−a³b³=a(6a²x−ax−a²b³)15x³y²+10x²y−20x³y³=6x²y(3xy+2-4xy²)
Մաթեմատիկա 06.09 September 30, 2019Anahit AvetisyanLeave a comment (x+2)⋅5=5x+10 1. (x+2)(x-3)=x²−x−66(3y-4)= 18y-24 2. (5x+1)(2x+4)=10x²+22x+4(2m+3n)⋅7=14m+21n 3. (3b+2)(4−b)=−3b²+10b+8c(2a+5b)=2ac+5bc 4. (2y−5)(4y-3)=8y²−26y+15-4a(3b-2a)=-12ab+8² 5. (3a+4)(2a−3)= 6a²−a−12 (m+n)(m−n)=m²−n² 1. 2x+2y=2(x+y)(p−q)(p+q)=p²−q² 2. 5m-5n=5(m−n)(c+d)(d−c)= d²−c² 3. 10q-5q=5(2p-q)(a-b)(b+a)=−b+a² 4. 12c+8b=4(3c+2b)(x+1)(x−1)=x²−1 5. 15t-9k=3(5t-3k)(a+2)(2−a)=4−a²